Math, asked by UTKARSH987654321, 11 months ago

If x+1/x = 8, Find the value of x²+1/x²

Answers

Answered by BrainlyUnnie
2

Answer:

x-+1/x = 8

 {x}^{2}  +  { \frac{1}{x} }^{2}

= 8^2 = 64

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Answered by binder1977dullat
1

x+1/x=8

squaring both sides

(X+1/X)^2+2=(8)^2

x^2+1/x^2+2=64

x^2+1/x^2=64-2

x^2+1/x^2=62

answer=62

I hope it will help you!!!

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