If x+1/x=9 and x^2 +1/x^2=53 then find
value of x-1/x??
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Answered by
12
since x+1/x=9
x+1=9x
x=1/8
now, putting the value of x
x=-7
x+1=9x
x=1/8
now, putting the value of x
x=-7
Answered by
12
x + 1/x = 9
You transpose x in 1/x to RHS ( Right Hand Side )
x + 1 = 9x
Now you transpose the x in the LHS ( Left Hand Side ) to the RHS ( Right Hand Side )
1 = 9x - x = 8x
8x = 1
Now you transpose the 8 to the RHS ( Right Hand Side )
x = 1/8
x - 1/x = 1/8 - ( 1 ÷ 1/8 )
Now we reciprocate ( switch the numerator and the denominator ) 1/8
x - 1/x = 1/8 - ( 1 × 8 )
x - 1/x = 1/8 - 8
x - 1/x = 1/8 - 64/8
x - 1/x = -63/8
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