if x+1/x = 9 , find value of x-1/x = ?
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x+1/x=9
Squaring both sides,
(x+1/x)²=81
x²+2×x×1/x+1/x²=81
x²+1/x²+2=81
x²+1/x²=79------------1)
(x-1/x)²=x²+1/x²-2×x×1/x
=x²+1/x²-2
=79-2-------------from 1)
=77
x-1/x=+/-√77
Squaring both sides,
(x+1/x)²=81
x²+2×x×1/x+1/x²=81
x²+1/x²+2=81
x²+1/x²=79------------1)
(x-1/x)²=x²+1/x²-2×x×1/x
=x²+1/x²-2
=79-2-------------from 1)
=77
x-1/x=+/-√77
Answered by
6
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▌│█║▌║▌║ Your answer ║▌║▌║█
Given that : - x + 1/x = 9
To find : - value of x - 1/x.
n̲̅o̲̅w̲̅,
x + 1/x = 9
=> (x + 1/x)² = (9)² [squaring both sides. ]
=> x² + 1/x² + 2 = 81
=> x² + 1/x² = 81 - 2
=> x² + 1/x² = 79
=> x² + 1/x² - 2 = 79 - 2 [subtracting 2 from both sides]
=>(x - 1/x)² = 77
=> x - 1/x = ±√77
h̲̅o̲̅p̲̅e̲̅ i̲̅t̲̅ h̲̅e̲̅l̲̅p̲̅s̲̅
▌│█║▌║▌║ Your answer ║▌║▌║█
Given that : - x + 1/x = 9
To find : - value of x - 1/x.
n̲̅o̲̅w̲̅,
x + 1/x = 9
=> (x + 1/x)² = (9)² [squaring both sides. ]
=> x² + 1/x² + 2 = 81
=> x² + 1/x² = 81 - 2
=> x² + 1/x² = 79
=> x² + 1/x² - 2 = 79 - 2 [subtracting 2 from both sides]
=>(x - 1/x)² = 77
=> x - 1/x = ±√77
h̲̅o̲̅p̲̅e̲̅ i̲̅t̲̅ h̲̅e̲̅l̲̅p̲̅s̲̅
AyushRawaat:
your answer is correct. thanks for helping me.
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