if x+1/x is 7 . then find x^3+1/x^3
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Given x + 1/x = 7.
On cubing both sides, we get
(x + 1/x)^3 = (7)^3
We know that (a + b)^3 = a^3 + b^3 + 3ab(a + b).
Here a = x, b = 1/x.
x^3 + 1/x^3 + 3 * x * (1/x)(x + 1/x) = 343
x^3 + 1/x^3 + 3(x + 1/x) = 343
x^3 + 1/x^3 + 3(7) = 343
x^3 + 1/x^3 = 21 = 343
x^3 + 1/x^3 = 343 - 21
x^3 + 1/x^3 = 322.
Hope this helps!
On cubing both sides, we get
(x + 1/x)^3 = (7)^3
We know that (a + b)^3 = a^3 + b^3 + 3ab(a + b).
Here a = x, b = 1/x.
x^3 + 1/x^3 + 3 * x * (1/x)(x + 1/x) = 343
x^3 + 1/x^3 + 3(x + 1/x) = 343
x^3 + 1/x^3 + 3(7) = 343
x^3 + 1/x^3 = 21 = 343
x^3 + 1/x^3 = 343 - 21
x^3 + 1/x^3 = 322.
Hope this helps!
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