Question

if x+1/x=root 3 ,then find the value ofxcube + 1/xcube
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Answer 1

x+1/x=, this is my answer

Answer 2

$Given : x + \frac{1}{x} = \sqrt{3}$

On cubing both sides, we get

$= > (x + \frac{1}{x})^3 = (\sqrt{3})^3$

$= > x^3 + \frac{1}{x^3} + 3 * x * \frac{1}{x}(x + \frac{1}{x}) = 3\sqrt{3}$

$= > x^3 + \frac{1}{x^3} + 3(x + \frac{1}{x}) = 3\sqrt{3}$

$= > x^3 + \frac{1}{x^3} + 3(\sqrt{3}) = 3\sqrt{3}$

$x^3 + \frac{1}{x^3} = 3\sqrt{3} - 3\sqrt{3}$

$= > x^3 + \frac{1}{x^3} = 0$

Hope this helps!