if x-1/x=root5 then find x^2-1/x^2
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x-1/x=√5
x-1=√5x
x-√5x-1=0
x=-b+-√b^2-4ac/2a
x=√5+-√5+4/2
x=√5+-3/2
x=√5+3/2,√5-3/2
when x=√5+3/2
x^2-1/x^2=(√5+3/2)^2-1/(√5+3/2)^2
=5+9-6√5-4/4÷5+9-6√5/4
=10-6√5/14-6√5
x-1=√5x
x-√5x-1=0
x=-b+-√b^2-4ac/2a
x=√5+-√5+4/2
x=√5+-3/2
x=√5+3/2,√5-3/2
when x=√5+3/2
x^2-1/x^2=(√5+3/2)^2-1/(√5+3/2)^2
=5+9-6√5-4/4÷5+9-6√5/4
=10-6√5/14-6√5
tushargumber:
wrong answer
how
the 2 is in division to whole the expression
in which step
see question again
it is x^2
ok
now is it right or not
May be wrong
ok
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