Question

If x+1/x = under root 5, find the value of x^2+1/×^2 and x^4+1/x^4 please answer for solutio
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Answer 1

Answer:

x²+1/x²=3 and x^4+1/x^4=7

Step-by-step explanation:

x+1/x = √5

squaring both sides

(x+1/x)² = (√5)²

x²+1/x²+2x*1/x=5

x²+1/x²+2=5

x²+1/x²=5-2=3

x²+1/x²=3-------------------------(1)

squaring both sides

(x²+1/x²)²=3²

x^4+1/x^4+2x² *1/x²=9

x^4+1/x^4+2=9

x^4+1/x^4=9-2=7

Hence x^4+1/x^4=7-------------(2)

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