Question

If x=1, y=1 is a solution of ax+4y=8 and x+3b=7, then the value of a-b= *

Answer 1

Answer:

2

Step-by-step explanation:

puting x = 1, y = 1 in ax+4y=8, we get

  a+4=8

Therefore, a=4.

Now, putting x = 1, y = 1 in x +3b=7, we get

 1+3b=7

 3b=6

b=2.

Therefore, a-b = 4-2 =2.

Answer 2

Answer:

a-b= 2

Step-by-step explanation:

x= 1

y= 1

ax+4y= 8

a(1) + 4(1)= 8

a+4= 8

Transposing 4 to RHS

a= 8-4

a= 4

x+3b= 7

1+ 3b= 7

Transposing 1 to RHS

3b =7-1

3b= 6

Transposing 3 to RHS

b= 6÷3

b= 2

Therefore, The value of a-b= 4-2

a-b= 2

Hope this helps you!