Question

If (x + 1, y – 2) = (3, 1), the values of x and y

(A) x=2, y=3 (B) x=4, y=3

(C) x=3, y=4 (D) x=3, y=2​

Answer 1

In the given question ordered pairs are equal. So, corresponding elements will also be equal.

$\huge\underline\bold{Answer:-}$

(x + 1, y – 2) = (3, 1)

$= > x + 1 = 3 \: \: \: \: ...(1)$

$= > y - 2= 1 \: \: ...(2)$

Solving 1

$= > x + 1 = 3 \\ = > x = 3 - 1 \\ = > x = 4$

Now solving 2

$= > y - 2 = 1 \\ = > y = 1 + 2 \\ = > y = 3$

Therefore, value of 'x' is 4 and value of 'y' is 3.

Option A is correct.

Answer 2

Step-by-step explanation:

ANSWER

Equation I = 2x + 3y = 5

Equation II = 7x - 4y = 3

Multiplying first equation by 4 =

→ 2x + 3y = 5

∴ (2x + 3y = 5) x (4)

= (8x + 12y = 20)......... (equation.III)

Now Multiplying second equation by 3 =

→ 7x - 4y = 3

∴ (7x - 4y = 3) x (3)

= (21x - 12y = 9).......... (equation IV)

Now, Add Equation III with Equation IV.

→ (8x + 12y = 20) + (21x - 12y = 9)

→ (8x + 21x) + (12y - 12y) = (20 + 9)

→ 29x + 0 = 29

→ 29x = 29

→ x = 29/29

→ x = 1

We get : x = 1,

Now Putting x = 1 in Equation I,

→ 2x + 3y = 5

→ 2(1) + 3y = 5

→ 2 + 3y = 5

→ 3y = 5 - 2

→ 3y = 3

→ y = 3/3

→ y = 1