Question

If x = 1,y=-2,and z=3,find the value of
1 x3+y3+z3-3xyz

Answer 1

Answer:

1×3+(-2)×3+(3)3-3(-2)(3)

3+(-6)+(9)-3(-6)

3+(-6)+(9)+18

3-6+9+18

3-6+27= 30-6=24

hope it may help uh

Step-by-step explanation:

if it is wrong ...just leave it

Answer 2

Answer:

38 is the answer

Step-by-step explanation:

x=1

y=-2

z=3

value of 1 x^3+y^3+z^3-3xyz is

1*(1)^3+(-2)^3+(3)^3-3*1*-2*3

= 1+(-8)+27+18

= 38 ans