Question

If x = 1, y = –2 and z = 3, Find the value of 5x + 3y – 2z – 3xyz. *​

Answer 1

Answer:

The value of 5x + 3y – 2z – 3xyz = 11

Step-by-step explanation:

It is given that x = 1, y = –2, and z = 3.

We have to find the value of 5x + 3y – 2z – 3xyz.

Putting the values of x, y, and z in 5x + 3y – 2z – 3xyz we get,

5x = 5 × 1 = 5

3y = 3 × (-2) = - 6

2z = 2 × 3 = 6

3xyz = 3 × 1 × (-2) × 3 = - 18

So, 5x + 3y – 2z – 3xyz = 5 + (-6) - 6 - (-18)

= 5 - 6 - 6 + 18 = 23 - 12 = 11

∴ The value of 5x + 3y – 2z – 3xyz = 11