Math, asked by thaparitika256, 5 months ago

if x =1 y =2 and z =3 find the value
x³+y³+z³–3xy3xy⁴–15x²y+4z​

Answers

Answered by yashrajdwivedi422
2

Answer:

-30

Step-by-step explanation:

x³+y³+z³-3xy⁴-15x²y+4z

1³+2³+3³-3+1+2+3+3+1+2⁴-15+1²+2+4+3

3+6+9-13+8-18+2+4+3

18-21-27

-3-27 = -30

answer is (-30)

Similar questions