if x=1, y=2 and z=5 find the value of 3x-2y+4z
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➡3x - 2y + 4z
➡3 × 1 - 2 × 2 + 4 × 5
➡3 - 4 + 20
➡3 + 16
➡19
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We have to find the value of 3x-2y+4z , when x = 1 , y = 2 and z = 5.
Solution :
3(1)-2(2)+4(5)
= 3-4+20
= 23 -4 = 19
Hence the value so required is 19.
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