Question

if x=1 ,y=2 is a solution of equation a2x+ay=3, then find the value of a

Answer 1

Answer:

a²x + ay = 3

x=1, y=2

Step-by-step explanation:

a²×1 + a×2 = 3

a² + 2a = 3

a² + 2a -3 = 0

a² + (3a-a) -3 = 0

a² + 3a - a -3 = 0

a ( a+3) - 1 (a+3) = 0

(a-1) (a+3) = 0

therefore, a= 1 and a= -3

Answer 2

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Now given x= 1 y = 1

by substituting values of x and y in given equation

a²(1) + a(1) = 3 or a²+ a = 3

then a² + a -3 = 0

by factorising (mid ter splitting)

a² + 3a -a -3

a(a + 3)-1(a+3)

(a-1)(a+3)

so a=1

or a= -3

hope it helps you

be brainly