if x=1,y=2 is a solution of the equation a^2x+ay=3, then find the values of a
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since
x=1,Y=2
a^2x+ay=3
a^2+2a-3=0
a^2+3a-1à-3=0
a(a+3)-1(a+3)=0
(a-1)(a+3)=0
therefore,
a=1,a=-3
Answered by
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Answer:
The values of a are - 3 and 1.
Step-by-step-explanation:
The given equation is a²x + ay = 3.
We have given that, x = 1 & y = 2 is a solution of the given equation.
We have to find the values of a.
Now, by substituting values of x and y in the given equation, we get,
a²x + ay = 3
⇒ a² * 1 + a * 2 = 3
⇒ a² + 2a = 3
⇒ a² + 2a - 3 = 0
⇒ a² + 3a - a - 3 = 0
⇒ a ( a + 3 ) - 1 ( a + 3 ) = 0
⇒ ( a + 3 ) ( a - 1 ) = 0
⇒ ( a + 3 ) = 0 , ( a - 1 ) = 0
⇒ a + 3 = 0 , a - 1 = 0
⇒ a = - 3 , a = 1
∴ The values of a are - 3 and 1.
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