Question

if x=1,y=2 is a solution of the equation a^2x+ay=3, then find the values of a​

Answer 1

since

x=1,Y=2

a^2x+ay=3

a^2+2a-3=0

a^2+3a-1à-3=0

a(a+3)-1(a+3)=0

(a-1)(a+3)=0

therefore,

a=1,a=-3

Answer 2

Answer:

The values of a are - 3 and 1.

Step-by-step-explanation:

The given equation is a²x + ay = 3.

We have given that, x = 1 & y = 2 is a solution of the given equation.

We have to find the values of a.

Now, by substituting values of x and y in the given equation, we get,

a²x + ay = 3

⇒ a² * 1 + a * 2 = 3

⇒ a² + 2a = 3

⇒ a² + 2a - 3 = 0

⇒ a² + 3a - a - 3 = 0

⇒ a ( a + 3 ) - 1 ( a + 3 ) = 0

⇒ ( a + 3 ) ( a - 1 ) = 0

⇒ ( a + 3 ) = 0 , ( a - 1 ) = 0

⇒ a + 3 = 0 , a - 1 = 0

⇒ a = - 3 , a = 1

∴ The values of a are - 3 and 1.