Question

If x=1, y=2 is solution of equation a2x + ay = 3. Find value of a.
Plz note that in equation a2x + ay = 3, it's a square x + ay= 3. I.e 2 is power of a.

Answer 1

Since x=1 and y=2 is a solution, it satisfies the equation.
So
${a}^{2} \times 1 + a \times 2 = 3 \\ {a}^{2} + 2a - 3 = 0 \\ (a + 3)(a - 1) = 0 \\ a = - 3 \: \: or \: \: 1$

Answer 2

Answer:

a = -3 or a=1  

Step-by-step explanation:

Equation is $a^2x+ay = 3$ ..............(1)

To find the value of a, Put x = 1 and y = 2 in (1)

We get,

$a^2(1) + a(2) =3$

$a^2 + 2a = 3$

$a^2 +2a-3 = 0$

Splitting the middle term,

$a^2 +3a - a -3 = 0$

a(a+3) -1(a+3) = 0

(a-1)(a+3) = 0

a-1 = 0 or a-3 = 0

a = -3 or a = 1