if x = -1, y = 2, z = -1, then prove that x -(y-z) is not equal to (x-y)-z
Answers
Answered by
4
Hi ,
It is given that ,
x = -1 , y = 2 , z = -1
x - ( y - z )
= ( - 1 ) - [ 2 - ( - 1 ) ]
= -1 - ( 2 + 1 )
= -1 - 3
= -4 ----( 1 )
( x - y ) - z
= [ -1 - 2 ] - ( - 1 )
= -3 + 1
= - 2 -------( 2 )
From ( 1 ) and ( 2 ) , we conclude that
x - ( y - z ) ≠ ( x - y ) - z
I hope this helps you.
: )
It is given that ,
x = -1 , y = 2 , z = -1
x - ( y - z )
= ( - 1 ) - [ 2 - ( - 1 ) ]
= -1 - ( 2 + 1 )
= -1 - 3
= -4 ----( 1 )
( x - y ) - z
= [ -1 - 2 ] - ( - 1 )
= -3 + 1
= - 2 -------( 2 )
From ( 1 ) and ( 2 ) , we conclude that
x - ( y - z ) ≠ ( x - y ) - z
I hope this helps you.
: )
ShouryaOjha1:
Yes it helped me, thanks for answering
Answered by
3
Putting the values in x-(y-z)
-1 - { 2 - (- 1) }
-1 - (2+1)
-1 - 3
-4
Solution of x -( y -z) is -4
-------------------------------
( x - y) - z
Putting the values,
(-1 -2)-(-1)
(-3) + 1
-3+1
-2
------------------------
It can be noticed that -4 is not equal to -2
So,
x - (y -z) is not equal to ( x -y)-z
I hope this will help you
-by ABHAY
-1 - { 2 - (- 1) }
-1 - (2+1)
-1 - 3
-4
Solution of x -( y -z) is -4
-------------------------------
( x - y) - z
Putting the values,
(-1 -2)-(-1)
(-3) + 1
-3+1
-2
------------------------
It can be noticed that -4 is not equal to -2
So,
x - (y -z) is not equal to ( x -y)-z
I hope this will help you
-by ABHAY
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