If x=1,y=2,z=3 find the value of x square+ y square+ z square+ 2xyz
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Answered by
15
x²+y²+z²+2xyz
=(1)²+(2)²+(3)²+2×1×2×3
=1+4+9+12
=26
=(1)²+(2)²+(3)²+2×1×2×3
=1+4+9+12
=26
Answered by
4
It is Given that,
x = 1
y = 2
z = 3
To Find the value of x² + y² + z² + 2xyz
Substituting the given value in x² + + y² + z² + 2xyz
we get,
= (1)² + (2)² + (3)² + 2×1×2×3
= 1 + 4 + 9 + 12
= 26
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