Question

if X=1,Y=2,Z=5,find the value of
(vi) x3 - y3- z3​

Answer 1

Answer:

${x}^{3} - {y}^{3} - z {}^{3} \\ = 1 {}^{3} - {2}^{3} - {5}^{3} \\ = 1 \times 1 \times 1 - 2 \times 2 \times 2 - 5 \times 5 \times 5 \\ = 1 - 8 - 5 \\ = - 7 - 5 \\ = - 12$

Answer 2

Answer:

Substituting x=1,y=2 and z=5 in the given expression, we get

x ^3 −y ^3 −z ^3 =(1) ^3 −(2) ^3 −(5) ^3

=(1×1×1)–(2×2×2)–(5×5×5)

=(1)–(8)–(125)

=1–8–125

=1–133

=−132

∴x ^3 −y ^3 −z ^3 =−132