Question

If x=1,y=2,z=5 then find the value of 2x square-3y square+Z square

Answer 1

$If \: x = 1 , \: y = 2 \:and \: z = 5 , \\then \: \red{Value \: of \: 2x^{2}-3y^{2} + z^{2}} \\= 2\times 1^{2} - 3 \times 2^{2} + 5^{2} \\= 2 \times 1 - 3 \times 4 + 25 \\= 2 - 12 + 25 \\= -10 + 25 \\= 15$

Therefore.,

$\red{Value \: of \: 2x^{2}-3y^{2} + z^{2}}\green { = 15 }$

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Answer 2

✰✰|| Solution :

2x² - 3y² + z²

= 2 × 1² - 3 × 2² + 5²

= 2 × 1 - 3 × 4 + 25

= 2 - 12 + 25

= 27 - 12

= 15