if x=1 y=6 is a solution of the equation 8x-ay+a2=0 find the value of a
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Step-by-step explanation:
put the value of x and y in the given equation
8x-ay+a^2=0
8-6a+a^2=0
a^2-6a+8=0
a^2-(4+2)a+8=0
a^2-4a-2a+8=0
a(a-4) -2(a-4) =0
(a-4) (a-2) =0
a=4 or a=2
now put again the value of a in the equation
yes these both are solution of the equation
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