Question

if (x+10)° and (2x-10)° are complementary angles to each other then find these angles

Answer 1

Answer:-

According to the Question

• One angle = (x+10)°

• Another angle = (2x-10)°

As we have to calculate the value of angles.

As we know that sum of angles is 90° then we call it complementary to each other .

Substitute the value we get

$:\implies$ (x+10)° + (2x-10) = 90°

$:\implies$ x+10 + 2x -10 = 90°

$:\implies$ 3x = 90°

$:\implies$ x = 90°/3

$:\implies$ x = 30°

Now, putting the value of x = 30° in the given angle

One angle = (x+10) = 30+10 = 40°

Another angle = (2x-10) = 2×30 -10 = 50°

• Hence, the angles are 40° & 50° respectively .

Answer 2

Step-by-step explanation:

Given:-

Two angles Mentioned below are complementary

• (x+10)°
• (2x-10)°

To find :-

Both angles

Solution:-

We know that

$\boxed{\sf Sum\:of\:Complementary\:angles=90^{\circ}}$

$\\ \tt{:}\Rrightarrow (x+10)+(2x-10)=90$

$\\ \tt{:}\Rrightarrow x+10+2x-10=90$

$\\ \tt{:}\Rrightarrow x+2x+10-10=90$

$\\ \tt{:}\Rrightarrow 3x=90$

$\\ \tt{:}\Rrightarrow x=\dfrac{90}{3}$

$\\ \tt{:}\Rrightarrow x=30$

Finding angles:-

$\\ \tt{:}\Rrightarrow x+10=30+10=\bf{40^{\circ}}$

$\\ \tt{:}\Rrightarrow 2x-10=2(30)-10=60-10=\bf{50^{\circ}}$

Thus the angles are 40° and 50°.