Question

if x=10 and y=20. Find the value of Z. When Z= x++ + ++y-x​

Answer 1

Answer:

z=x+y

z=10+20

20-10=z

z=10

Answer 2

Answer:

Given,

• x=10
• y=20

$\begin{gathered} \tt \orange{ Z=x++ \: \: + \: \: ++y \: \: -x} \\ : \implies \tt10 + \: \: + + y \: \: - x \\ \backslash \backslash \green{ \tt \: now \: x \: becomes \: 11 \: and \: y = 21} \\ : \implies \tt10 + 21 - x \\ : \implies \tt10 + 21 - 11 \\\backslash \backslash \green{ \texttt{\: now \: follow \: BEDMAS \: rule}} \\ : \implies \tt31 - 11 \\ : \implies\tt\orange{ \underline{ \boxed{20}}}\end{gathered}$

$\begin{gathered}\dag\tt{\large{\bold{Note}:\begin{cases}\sf{ ++x\:and\:--x\:are\:prefix\:increment/decrement\:operator}\\\sf{x++\:and\:x--\:are\:postfix\:increment/decrement\:operator}\\\sf{Postfix\:operator\:increases\:its\:value\:after\:moving\:forward}\\\sf{Prefix\:operator\:increases\:its\:value\:before\:moving\:forward}\end{cases}}}\end{gathered}$