Question

if x 10 square 60 degree + 3 sin square 60 degree minus 3 upon 4 10 square 30 degree equals to 6 ​

Answer 1

Answer:

57/8

Step-by-step explanation:

x tan2 60°+ 3sin2 60°- 3/4 tan2 30°= 6

= x(1/√3)2 + 3 ( 2/√3)2- 3/4 (1/2)=6

= x/3+4-3/8=6

= x/3 + (32-3)/8 =6

= x/3 + 29/8 =6

= x/3 =6 - 29/8

= x/3 =48 -29/8

= x/3 =19/8

= x =57/8 ...ans..

Answer 2

The value of x is $x=\frac{3}{2}$

Step-by-step explanation:

Given : Expression $x\tan^2 60^\circ+3\sin^2 60^\circ-\frac{3}{4}\tan^2 30^\circ=6$

To find : The value of x ?

Solution :

$x\tan^2 60^\circ+3\sin^2 60^\circ-\frac{3}{4}\tan^2 30^\circ=6$

Using trigonometric values,

$\tan 60^\circ=\sqrt{3}$

$\sin 60^\circ=\frac{\sqrt{3}}{2}$

$\tan 30^\circ=\frac{1}{\sqrt{3}}$

Substitute the values,

$x(\sqrt{3})^2+3(\frac{\sqrt{3}}{2})^2-\frac{3}{4}(\frac{1}{\sqrt{3}})^2=6$

$3x+3(\frac{3}{4})-\frac{3}{4}(\frac{1}{3})=6$

$3x+\frac{9}{4}-\frac{1}{4}=6$

$\frac{12x+9-3}{4}=6$

$12x+6=24$

$12x=18$

$x=\frac{18}{12}$

$x=\frac{3}{2}$

Therefore, the value of x is $x=\frac{3}{2}$

#Learn more

1-tan^2 60/1+tan^2 60= cos a then find a

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