Question

If x=10,y=0,z=5, then find the value of x+y-2z?

Answer 1

$\huge\bf{\underline{\underline{\red{Solution:-}}}}$

$\sf\underline{\blue{Given:-}}$

$\sf\bullet x=10\\ \\ \sf\bullet y=0\\ \\ \sf\bullet z=5\\ \\ \sf\:\:we\:have\:to\:find\:the\: value\:of\\ \\ \sf\implies {\purple{x+y-2z}}\\ \\ \sf\:\:\:\:\:\:\:\:\:\:Then$

$\sf\underline{\red{A.T.Q:-}}$

$\sf:\implies x+y-2z\\ \\ \sf{\blue{Now\: put\:the\: value\:of\:x,\:y\:and\:z}}$

$\sf:\implies 10+0-2\times 5\\ \\ \sf\implies 10+0-10\\ \\ \sf\implies{\purple{x+y-2z= 0}}$

$\boxed{\sf{\red{x+y-2z=0}}}$

Answer 2

$\bf \red{Given}$

• x=10
• y=0
• z=5

To find out:- x+y-2z

solutions:

$\blue{x + y - 2z}$

$putting \: the \: value \: of \: x \: y \: and \: z$

$\orange{10 + 0 - 2 \times 5}$

$\green{10 + 0 - 10}$

$\pink{10 - 10}$

$\purple{x + y - 2z = 0}$