Question

if x=10,y=3,find (x+y)2 and (2x+3y)2.​

Answer 1

Answer:

$\huge\mathcal{\star{\colorbox{orange}{Answer}}}$

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Given:-

$\sf{\color{aqua}{x = 10}}$

$\sf{\color{aqua}{y= 3}}$

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Proof:-

$\sf\green{⇒(x + y)2}$

$\sf\blue{⇒(10 + 3)2 \: = 0}$

$\sf\blue{⇒(13)2}$

$\sf\blue{⇒26}$

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$\sf\green{⇒(2x + 3y)2}$

$\sf\blue{⇒(2(10) + 3(3))2}$

$\sf\blue{⇒(20 + 9)2}$

$\sf\blue{⇒(29)2}$

$\sf\blue{⇒58}$

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$\huge\mathbf\red{\underline{\underline{Be \: brainly}}}$

Answer 2

Given:-

x = 10

y = 3

Proof:-

⇒(x+y)2⇒(x + y)2⇒(x+y)2

⇒(10+3)2=0⇒(10 + 3)2 \: = 0⇒(10+3)2=0

⇒(13)2

⇒(2x+3y)2⇒(2x + 3y)2⇒(2x+3y)2

⇒(2(10)+3(3))2⇒(2(10) + 3(3))2⇒(2(10)+3(3))2

⇒(20+9)2⇒(20 + 9)2⇒(20+9)2

⇒(29)2⇒

⇒58