If (x^100+2x^49+k) is divisible by x+1 find value of k
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Answer:
k=1
Step-by-step explanation:
x+1=0
x=-1
(x^100+2x^49+k)=0
(-1)^100+2(-1)^49+k=0
1+(-2)+k=0
(-1)+k=0
k=1
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