if x^100 + 2x^99 + k is divisible by (x + 1).....find the value of K
Answers
Answered by
7
Answer:
k=1
Step-by-step explanation:
since x^100+2x^99+k is divisible by x+1
=> if (x+1)=0 or x= -1 is substituted in the
polynomial it becomes zero.
=> (-1)^100+2(-1)^99+k=0
=> 1-2+k= = 0
=> k= 1
Similar questions