Question

If x=1001,y=1002,z=1003,find the value of x^3+y^3+z^3-3xyz ,without actually calculating cubes

Answer 1

x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx)

Ans : 9018

Answer 2

Answer:

Step-by-step explanation: Good question