If x=1001, y=1002,z=1003 find the value of x³+y³+z³-3xyz=½ (x+y+z+) [(x-y)²+(y-z)² +(z-x)²]
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Answer:
= 9018
Step-by-step explanation:
= 1/2*(1001+1002+1003)second bracket start (1001-1002)hole square + (1002-1003)hole square + (1003-1001)hole square sceond bracket end
= 1/2*3006(1+1+4)
=1/2*3006*6
=1*3006*6
=9018 (Answer)
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