Question

If x = {(-11)^5}^4, and y = {(-11)^2}^3, find the value of x^3 ÷ y^3.
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Answer 1

Step-by-step explanation:

$x = ( { - 11}^{5} ) {}^{4} \\ y = ( - 11 {}^{2} ) {}^{3} \\ \\ \\ \frac{ {x}^{3} }{ {y}^{3} } = find \\ \\ {x}^{3} = (- 11 {}^{20} ) {}^{3} \\ = - 11 {}^{23} \\ {y}^{3} = ( - 11 {}^{6} ) {}^{3} \\ = - 11 {}^{18} \\ \frac{ {x}^{3} }{ {y}^{3} } = \frac{ - 11 {}^{23} }{ - 11 {}^{18} } \\ = 11 {}^{23 - 18} \\ = 11 {}^{5}$

Answer 2

Step-by-step explanation:

\begin{gathered}x = ( { - 11}^{5} ) {}^{4} \\ y = ( - 11 {}^{2} ) {}^{3} \\ \\ \\ \frac{ {x}^{3} }{ {y}^{3} } = find \\ \\ {x}^{3} = (- 11 {}^{20} ) {}^{3} \\ = - 11 {}^{23} \\ {y}^{3} = ( - 11 {}^{6} ) {}^{3} \\ = - 11 {}^{18} \\ \frac{ {x}^{3} }{ {y}^{3} } = \frac{ - 11 {}^{23} }{ - 11 {}^{18} } \\ = 11 {}^{23 - 18} \\ = 11 {}^{5} \end{gathered}

x=(−11

5

)

4

y=(−11

2

)

3

y

3

x

3

=find

x

3

=(−11

20

)

3

=−11

23

y

3

=(−11

6

)

3

=−11

18

y

3

x

3

=

−11

18

−11

23

.

=11

23−18

=11

5