Question

If x=-12 is a solution of the quadratic equation 3x'2 + 2x +3 =0, find the value of K​

Answer 1

Correct Question:

If x = -12 is a solution of the quadratic equation 3x² + 2kx +3 =0, find the value of K

Answer:

k is 18.125

Step-by-step explanation:

Quadratic equation is 3x² + 2kx + 3 = 0 and x is -12.

To find: value of k

Substitute value of x = -12 in 3x² + 2kx + 3 = 0

→ 3(-12)² + 2k(-12) + 3 = 0

→ 3(144) - 24k + 3 = 0

→ 432 - 24k + 3 = 0

→ 435 - 24k = 0

→ 24k = 435

→ k = 435/24

→ k = 18.125

Hence the value of k is 18.125.

Answer 2

Answer:

✔CORRECT QUESTION ✔

If x=-12 is a solution of the quadratic equation 3x² + 2kx +3 =0, find the value of K

⭐ Given ⭐

Quadratic equation is

3x² + 2kx +3 =0 and x = -12

⭐ To find ⭐

Substitute value of x = -12 in

3x² + 2x +3 =0

ATQ:-

=> 3(-12)²+2kx+3 = 0

=> 3(-12)²+2k(-12)+3=0

=>3(144)-24+3 = 0

=> 432-24k+3 = 0

=> 435-24k = 0

=> 24k = 435

=> k = 435/24

=> k = 18.125

➡ Hence, the value of k is 18.125

Step-by-step explanation:

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