If x= (-12 ), is a solution of the quadratic equation 3x2+2kx-3=0, find the value of k
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0
Answer:
I don't know these types of equation
Answered by
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Answer: k = -75/24
Step-by-step explanation: 3x2 + 2kx - 3 = 0
Substituting x = -12 in the equation
6*-12 + 2*-12*k - 3 = 0
-72-3 + (-24k) = 0
-75 + (-24k) = 0
taking -75 on the other side
-24k = 75
k = 75/-24
k = -75/24
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