Question

if x=-12 is the zero of the polynomial 8x3 -ax2 -x+2 find a

Answer 1

hey buddy,

here is your ans..

Step-by-step explanation:

$p(x) = 8 {x}^{3} - ax {}^{2} - x + 2 \\ p( - 12) = 8( - 12) {}^{3} - a( - 12) {}^{2} - ( - 12) + 2 = 0 \\ = 8( - 1728) - a(144) + 12 + 2 = 0 \\ = 13824 - 144a + 14 = 0 \\ = - 144a = - 13838 \\ = a = \frac{ - 13838}{ - 144} \\ a = 96.097$

I hope it helps you

thank you

have a great evening ✌☺

Answer 2

Answer:

a=96.09

Step-by-step explanation:

if x=-12

p(x)=8x^3-ax^2-x+2

put x value in p(x)

p(-12)=8×12^3-a×12^2-(-12)+2

8×1728-a×144+12+2

13824-144a+12+2

13838-144a

=-144a=-12438

=144a=12438

=a=13838/144

=a=96.09