Question

If x^120+4x^143+k is divisible by x+1, then value of k is:​

Answer 1

Step-by-step explanation:

$= > if \: \: {x}^{120} + 4 {x}^{143} + k \: \: is \: \: divisible \: \: by \: \: x + 1$

$then \: \: x = - 1 \: is \: \: a \: \: solution$

Put x = -1.

$= > ({ - 1)}^{120} + 4( { - 1)}^{143} + k = 0$

=> 1 -4 +k = 0

=> k = 3.

:-) Hope it helps u.