Question

if x=√(13+4√10) then find the value of x+1\x​

Answer 1

Step-by-step explanation:

$x = \sqrt{13 + 4\sqrt{10} } \\ x + \frac{1}{x} = \sqrt{13 + 4\sqrt{10} } + \frac{1}{\sqrt{13 + 4\sqrt{10} } } \\ = \frac{ {(\sqrt{13 + 4\sqrt{10} })}^{2} + 1 }{\sqrt{13 + 4\sqrt{10} }} \\ = \frac{13 + 4 \sqrt{10} + 1}{\sqrt{13 + 4\sqrt{10} }} \\ = \frac{14 + 4 \sqrt{10} }{\sqrt{13 + 4\sqrt{10} }}$

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