Question

If x^140 +2x^151+k is divisible by x+1 then value of k is

Answer 1

Zero of ( x + 1 ) = -1.

By Remainder Theorem,

P ( x ) = x ^ 140 + 2 x ^ 151 + k

P ( 1 ) = ( -1 ) ^ 140 + 2 ( -1 ) ^ 151 + k = 0

             1 + 2 ( -1 ) + k = 0

             1 -2 + k = 0

            -1 + k = 0

              k = 1.

Answer 2

Answer:

Zero of ( x + 1 ) = -1.

By Remainder Theorem,

P ( x )= x ^ 140 + 2 x ^ 151 + k

P ( 1 ) = ( -1 ) ^ 140 + 2 ( -1 ) ^ 151 + k = 0

            1 + 2 ( -1 ) + k = 0

            1 -2 + k = 0

           -1 + k = 0

             k = 1.

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