Question

if (x+1upon x)=5 find the value of (x^2+1upon x^2) and (x^4+1upon x^4)​

Answer 1

$\huge\blue{ANSWER}$

IT'S GIVEN THAT

X+1/5=5

TO FIND X⁴+1/X⁴

X+1/X=5

SQUARE BOTH SIDES

(x+1/x)²=5²

x²+1/x²+2×x×1/x=25

X²+1/X²+2=25

X²+1/X²=25-2

x²+1/x²=23

AGAIN SQUARE BOTH SIDES

(x²+1/x²)²=23²

X⁴+1/X⁴+2×X²×1/X²=529

x⁴+1/x⁴+2=529

x⁴+1/x⁴=529-2

x⁴+1/x⁴=527

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