Question

If [x+1uponx]=12,find the value of [x²+1uponx²​

Answer 1

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$x + \frac{1}{x} = 12$

To find:-

${x}^{2} + \frac{1}{ {x}^{2} } = ?</p><p>$

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see ⇑⇑⇑in the picture above attach for complete solution step by step:-

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