Question

If x = 2(0 + sino) and y = 2(1 - cosa), then value of dy /dx​

Answer 1

Answer:

dy/dθ = a (0 -(-sinθ)) = a sin θ  

dx/dθ = a (1+cos θ)  

dy/dθ divided by dx/dθ = sin θ/ 1+cosθ  

At θ = π/2  

dy/dx = 1/1+0  

dy/dx = 1

Explanation:

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