Question

if (x^2+1\1x^2) =66 fund tge the value of x- 1\x​

Answer 1

Answer:

${x}^{2} + \frac{1}{ {x}^{2} } = 66 \\ subract \: 2 \times x \times \frac{1}{x} \: to \: both \: side \\ {x }^{2} + \frac{1}{ {x}^{2} } - 2x \times \frac{1}{x} = 66 - 2 \\( x - \frac{1}{x} ) ^{2} = 64 = {8}^{2} \\ x - \frac{1}{x} = 8$

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Answer 2

Answer:

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