if x =√2+1/√2-1 and y=√2-1/√2+1 then find the value of x²+y²+xy
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x = √2 + 1 = (√2 + 1) (√2 +1) = (√2 + 1)² = 3 + 2√2+1= 3+2√2
√2 - 1 (√2 - 1) (√2 + 1) (√2)² - 1² 2 - 1
x² = (3+2√2+)² = 9 + 8 + 12√2 = 17 + 12√2
y = √2 - 1 = (√2 - 1) (√2 - 1) = (√2 - 1)² = 3 - 2√2
√2 + 1 (√2 + 1) (√2 -1) 2 - 1
y² = (3-2√2)² = 9 + 8 - 12√2 = 17 - 12√2
xy = (3+2√2) (3-2√2) = 9 - 8 = 1
x² + y² + xy = 17 + 12√2 + 17 - 12√2 + 1 = 35
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