If x^2+1/×^2=47 then find the value of x^3+1/x^3
Answers
Answered by
6
Hi ,
x² + 1/x² = 47
x² + 1/x² + 2 = 47 + 2
( x + 1/x )² = 49
( x + 1/x )² = 7²
x + 1/x = 7 ---( 1 )
Now ,
x³ + 1/x³ = ( x + 1/x )³ - 3( x + 1/x )
= 7³ - 3 × 7
= 7( 7² - 3 )
= 7( 49 - 3 )
= 7 × 46
= 322
I hope this helps you.
: )
x² + 1/x² = 47
x² + 1/x² + 2 = 47 + 2
( x + 1/x )² = 49
( x + 1/x )² = 7²
x + 1/x = 7 ---( 1 )
Now ,
x³ + 1/x³ = ( x + 1/x )³ - 3( x + 1/x )
= 7³ - 3 × 7
= 7( 7² - 3 )
= 7( 49 - 3 )
= 7 × 46
= 322
I hope this helps you.
: )
Answered by
3
x² + 1/x² = 47
Adding 2 [ x × 1/x]
x² + 1/x² + 2(x × 2/x) = 47 + 2(x × 1/x)
(x + 1/x)² = 49
x + 1/x = 7
====================
x³ + 1/x³ =>
(x + 1/x) (x² + 1/x² - 1)
(7)(47 - 1)
7 × 46
322
I hope this will help you
(-:
Adding 2 [ x × 1/x]
x² + 1/x² + 2(x × 2/x) = 47 + 2(x × 1/x)
(x + 1/x)² = 49
x + 1/x = 7
====================
x³ + 1/x³ =>
(x + 1/x) (x² + 1/x² - 1)
(7)(47 - 1)
7 × 46
322
I hope this will help you
(-:
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