Question

if x^2+1/25x^2=27 find the Vale of 3x^3±5x-3/x^3-5/x​

Answer 1

Answer:

We know that(a-b)^2=a^2+b^2–2ab

Putting a=x,b=1/x

(x-1/x)^2=x^2+1/x^2–2×x×1/x

=x^2+1/x^2–2

=27–2=25

(x-1/x)^2=25

Taking squareroot of both sides

x-1/x=5

Now(3x^3–3/x^3)+(5x-5/x)

=3(x^3–1/x^3)+5(x-1/x)

=3(x-1/x)(x^2+1/x^2+1)+5×5

=3×5×(27+1)+25

=15×28+25

=420+25=445

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