Question

If x= 2^1/3-2^-1/3
, prove that 2x^3 +6x = 3.​

Answer 1

x= 2^1/3-2^(-1/3)

or, x³ =[2^ (1/3) −2 ^−(1/3) ]³

or, x³=[2^(1/3) ]³ −[2 ^−(1/3) ]³ −3(2^1/3)[2^−(1/3) ][2^1/3−2^−(1/3) ]

or, x³= 2 -(1/2) -3x

or ,x³+3x= 2-(1/2)

or, x³+3x= 3/2

so ,2x³+6x= 3 ( proved )

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