If x=2^1/3+2^2/3 , prove that x^3-6x=6
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by cubing given x we get the answer
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Taking x= 2^(2/3) + 2^(1/3) we get x = (cube root of 2) ^2 + (cube root of 2) ... If a^2+b^2+c^2+1/a^2+1/b^2+1 /c^2=6 then how do I prove that a^2+b^2+c^2=3?
please mark brainest
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