Question

if x= √2+1 find the value of (x-1/x)^2

Answer 1

Answer:

x = √2 + 1

$(\frac{x-1}{x} )^{2}$

= $(\frac{\sqrt{2} + 1 -1 }{\sqrt{2} +1 } )^{2}$

=$(\frac{\sqrt{2} }{\sqrt{2} +1 })^{2}$

= $(\sqrt{2} X (\sqrt{2} - 1))^{2}$

= $(2 - \sqrt{2} )^{2}$

= 4 - 4√2 + 2

= 6 - 4√2