If x=√2 + 1
Find value of
a) 1
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x
b) x+ 1
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x
c) x(square) + 1/x(square)
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a) 1/ x = 1/(√2 + 1) = (√2 - 1) / (2 - 1) = √2 -1
b) 1 + 1/x = 1 + √2 - 1 = √ 2
c) x² + 1/x² = (x+1/x)² - 2 = (√2 + 1 + √ 2 - 1)² - 2 = (2√2)² - 2 = 8 - 2 = 6
b) 1 + 1/x = 1 + √2 - 1 = √ 2
c) x² + 1/x² = (x+1/x)² - 2 = (√2 + 1 + √ 2 - 1)² - 2 = (2√2)² - 2 = 8 - 2 = 6
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