if x= √2+1,find value of x square+ 1÷x square
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(root2 +1)square
(2)square+2(root2)(1)+(1)square
2+2root2+1=3+2root2
x square +1 ÷ x square
3+2 root 2 +1 ÷ 3+2root2
ANSWER = 4+2root2/3+2root2
(2)square+2(root2)(1)+(1)square
2+2root2+1=3+2root2
x square +1 ÷ x square
3+2 root 2 +1 ÷ 3+2root2
ANSWER = 4+2root2/3+2root2
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3.33 is the answer to the question
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