if x^2 -1 is a factor of ax^3+bx^2+cx+d. Show that a+c = 0
Answers
Answered by
4
Answer:
let p(x) =x^3+bx^2+cx+d
(x^2-1)is a factor
x^2-1=0
x^2=1
x=+1 or -1
p(1)=a×1+b×1+c×1+d=0
a+b+c+d=0
a+c=-b-d...(1)
p(-1)=-a+b-c+d=0
a+c=b+d...(2)
adding (1) and (2) we get,
2(a+c)=0
a+c=0
hence proved
hope it helps.
Similar questions